As some of you know, Hou Yifan intentionally lost her last game in Gibraltar as a protest against artificial pairings. She had to play 7 women in 10 rounds. Her logic was fairly simple: it's just almost impossible to have 7 female players in 10 rounds, because there were just 37 women players among 255 participants.
I decided to check, how low the probability of having 7 or more women is.
a) A basic calculation. We don't know how works the Swiss System, everyone has an equal chance to play Hou Yifan. Hou Yifan can't play with herself, so we have 254 potential opponents and 36 women. The probability of 7 out of 10 women is:
P(7)= (36*35*34*33*32*31*30*218*217*216) / (254*253*252*251*250*249*248*247*246*245) * 120.
120 is the number of different combinations 7 out of 10. 10!/ (7!*3!) = 10*9*8/6 = 120.
P(7)= 0.000055 = 0.0055%.
That means, these strange pairings should happen every 18.000 events.
Theoretically, we should add the probability of having 8, 9, or even 10 female opponents. Sure, P(8) is much lower than P(7). I don't want to enter additional calculations, so we can estimate:
P(7-10) = 0.00006 = 0.006%. This is the probability of playing at least 7 women players in 10 rounds.
b) Now we can take into account some rules of swiss pairings and make 2 adjustments:
1. Hou Yifan was at 22nd ranking position and played close to her rating the whole tournament. In this case, it's very unlikely for her to face somebody from the lower half of the tournament, except for the 1st round.
2. In a big swiss event, one usually doesn't play against the opponent with a very close rating (or ranking). A "dead zone" is around 60 points in this kind of event. In other words, Hou Yifan could not play against opponents with 2591-2711 rating.
Indeed, she played against a "bottom half" opponent only in 1st round and never played against 2591-2711 players. Taking 1 and 2 into account, we reduce the number of potential opponents to 1-10 and 36-125 ranking. So, we have exactly 100 potential opponents and 25 women among this group.
Now, the probability of playing against women is much higher. 25/100 = 25%. In previous example (basic calculation) we had 36/254=14.2%.
Using the similar formula, we get
PP(7)= (25*24*23*22*21*20*19*75*74*73) / (100*99*98*97*96*95*94*93*92*91) * 120 = 0.0019 = 0.19%.
By adding to this number PP(8), PP(9) and PP(10) we should get about
PP (7-10) = 0.22%
So, these 2 adjustments changed the probability from P(7-10)= 0.006% to PP(7-10) = 0.22%, that means almost 40 times higher.
0.22% means that such a strange pairing could happen every 450 cases. Taking into account the total number of players in Gibraltar, this situation should happen every second tournament with one of the players.
I decided to check, how low the probability of having 7 or more women is.
a) A basic calculation. We don't know how works the Swiss System, everyone has an equal chance to play Hou Yifan. Hou Yifan can't play with herself, so we have 254 potential opponents and 36 women. The probability of 7 out of 10 women is:
P(7)= (36*35*34*33*32*31*30*218*217*216) / (254*253*252*251*250*249*248*247*246*245) * 120.
120 is the number of different combinations 7 out of 10. 10!/ (7!*3!) = 10*9*8/6 = 120.
P(7)= 0.000055 = 0.0055%.
That means, these strange pairings should happen every 18.000 events.
Theoretically, we should add the probability of having 8, 9, or even 10 female opponents. Sure, P(8) is much lower than P(7). I don't want to enter additional calculations, so we can estimate:
P(7-10) = 0.00006 = 0.006%. This is the probability of playing at least 7 women players in 10 rounds.
b) Now we can take into account some rules of swiss pairings and make 2 adjustments:
1. Hou Yifan was at 22nd ranking position and played close to her rating the whole tournament. In this case, it's very unlikely for her to face somebody from the lower half of the tournament, except for the 1st round.
2. In a big swiss event, one usually doesn't play against the opponent with a very close rating (or ranking). A "dead zone" is around 60 points in this kind of event. In other words, Hou Yifan could not play against opponents with 2591-2711 rating.
Indeed, she played against a "bottom half" opponent only in 1st round and never played against 2591-2711 players. Taking 1 and 2 into account, we reduce the number of potential opponents to 1-10 and 36-125 ranking. So, we have exactly 100 potential opponents and 25 women among this group.
Now, the probability of playing against women is much higher. 25/100 = 25%. In previous example (basic calculation) we had 36/254=14.2%.
Using the similar formula, we get
PP(7)= (25*24*23*22*21*20*19*75*74*73) / (100*99*98*97*96*95*94*93*92*91) * 120 = 0.0019 = 0.19%.
By adding to this number PP(8), PP(9) and PP(10) we should get about
PP (7-10) = 0.22%
So, these 2 adjustments changed the probability from P(7-10)= 0.006% to PP(7-10) = 0.22%, that means almost 40 times higher.
0.22% means that such a strange pairing could happen every 450 cases. Taking into account the total number of players in Gibraltar, this situation should happen every second tournament with one of the players.
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